5y/y^2-2y

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Solution for 5y/y^2-2y equation: 


D( y )

y^2 = 0

y^2 = 0

y^2 = 0

1*y^2 = 0 // : 1

y^2 = 0

y = 0

y in (-oo:0) U (0:+oo)

(5*y)/(y^2)-(2*y) = 0

(5*y)/(y^2)-2*y = 0

5*y^-1-2*y^1 = 0

(5*y^0-2*y^2)/(y^1) = 0 // * y^2

y^1*(5*y^0-2*y^2) = 0

y^1

5-2*y^2 = 0

5-2*y^2 = 0

DELTA = 0^2-(-2*4*5)

DELTA = 40

DELTA > 0

y = (40^(1/2)+0)/(-2*2) or y = (0-40^(1/2))/(-2*2)

y = (-10^(1/2))/2 or y = (1*10^(1/2))/2

y in { (-10^(1/2))/2, (1*10^(1/2))/2} 

y in { (-10^(1/2))/2, (1*10^(1/2))/2 }

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